Question

A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is :

• A. 1600 J
• B. 150 J
• C. 600 J
• D. 900 J

Answer 1

Answer: (B)

150 J

We know that

Total amount of work done$=$Area under $P-V$ diagram

According to $P-V$ diagram

Work done is process$=$Area of trapezium ABCDA

$=\frac{1}{2}\times AD\times (AB+DC)$

$=\frac{1}{2}\times (2-1)\times {10}^2(2+1)$

$=\frac{1}{2}\times 3\times {10}^2=150J$

The process is clockwise, so work done by the process is positive.

Hence amount of work done by gas$=+150$J.