Question

A cyclist comes to a skidding stop in $10m$. During this process, the force on the cycle due to the road is $200N$ and is directly oppose to the motion.

(a) How much work does the road do on the cycle?

(b) How much work does the cycle do on the road?

Answer 1

(a) Given Force on the cycle due to the road= 200 N and distance traveled during skidding before stopping =10 m

Work done = force$\times$displacement

=200$\times$10=$-2000J$ (negative sign used as applied in the direction opposite to that of motion

(b) zero