A cyclist follows the path from A to E as shown.

Calculate the distance and displacement, respectively. (1 unit = 2 km)

20 km and 2√10 km

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2√10 km and 20 km

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10√2 km and 10 km

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10 km and 10√2 km

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Solution

The correct option is A 20 km and 2√10 km
Distance = AB + BC + CD + DE = 4 + 2 + 3 + 1 = 10 units = 20 km

Displacement = AE = √ ((AO)²+ (OE)²) = √ ((1)²+ (3)²) = √10 units = 2√10 km

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A cyclist follows the path from A to E as shown. Calculate the distance and displacement, respectively. (1 unit = 2 km)

The correct option is A 20 km and 2√10 km Distance = AB + BC + CD + DE = 4 + 2 + 3 + 1 = 10 units = 20 km Displacement = AE = √ ((AO)²+ (OE)²) = √ ((1)²+ (3)²) = √10 units = 2√10 km

A cyclist follows the path from A to E as shown.

Calculate the distance and displacement, respectively. (1 unit = 2 km)

The correct option is A 20 km and 2√10 km
Distance = AB + BC + CD + DE = 4 + 2 + 3 + 1 = 10 units = 20 km

Displacement = AE = √ ((AO)²+ (OE)²) = √ ((1)²+ (3)²) = √10 units = 2√10 km