A cyclist follows the path from A to E as shown in the given diagram.
Calculate the distance and displacement with 1unit=2km.
A
10√2km and 10km
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B
10km and 10√2km
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C
20km and 2√10km
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D
2√10km and 20km
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Solution
The correct option is C20km and 2√10km To calculate the distance just add all the lengths of the line segments.
So, total distance is,
AB + BC + CD + DE = 8+4+6+2=20km
To find the displacement, we use the Pythagoras theorem. The shortest path to reach E from A is a line joining A and E.