In this question we will calculate the negative acceleration/deceleration, as follows:
Kinematic equations:
SUVAT-- s-displacement, u-initial velocity, v-final velocity,a- acceleration, t-time
v=u + at
v^2 = u^2 + 2as
s=1/2(u+v)t
s=ut + 1/2at^2
Her initial velocity, u is 15m/s
Her final velocity is, v 0m/s (since she stops)
Displacement is, s 18m
Hence the acceleration, a :
v^2=u^2 + 2as
0=15^2 + 2 x a x 18
0=225 + 36a
36a= -225
a = -225/36
a= -6.25 m/s/s
Therefore she has to decelerate at the rate of 6.25m/s2