Question

A cyclist is travelling at 15 $m{S}^{-1}$ accelerates at 0.5 $m{s}^{-2}$ for 30 s. How far will it travel in this time?

Answer 1

Step 1, Given data

Speed = 15 m/s

Acceleration = 0.5 m/$s^2$

Time = 30 sec

Step 2, Finding the distance traveled

From the equation of motion

We know,

$s=ut+\frac{1}{2}a{t}^2$

Putting all the values

$s=15\times 30+\frac{1}{2}\times \frac{1}{2}\times 30\times 30$

After solving

S = 675 m

Hence the distance traveled is 675 m