A cyclist moving at a speed of $20$ m/s takes a turn, if he doubles his speed then change of overturn

is doubled

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is halved

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becomes four times

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becomes 1/4 times

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Solution

The correct option is C becomes 1/4 times
When a cyclist moves on a circular path , it experience a centrifugal force which is equal to $m v^{2} / r$ .It tries to overturn the cyclist in outward direction.If speed increase twice, the value of centrifugal force too increase to 4 times its earlier value.Therefore the change of overturning in 1/4 times.

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