A cyclist rides from the bottom of a slope to the top and gains 10000 J of gravitational potential energy. She rolls down her bicycle freely to the bottom of the slope, and her kinetic energy is 2000J.
How much energy is dissipated in overcoming friction.

2000 J

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8000 J

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10000 J

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12000 J

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Solution

The correct option is B 8000 J
Total energy is always conserved.
So, total energy at top = total energy at bottom
10000 J + 0 = 0 + 2000 J + energy lost due to friction
(10000 - 2000) J = energy lost due to friction
So, the energy lost due to friction = 8000 J

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A cyclist rides from the bottom of a slope to the top and gains 10000 J of gravitational potential energy. She rolls down her bicycle freely to the bottom of the slope, and her kinetic energy is 2000J. How much energy is dissipated in overcoming friction.

The correct option is B 8000 JTotal energy is always conserved. So, total energy at top = total energy at bottom 10000 J + 0 = 0 + 2000 J + energy lost due to friction (10000 - 2000) J = energy lost due to friction So, the energy lost due to friction = 8000 J

A cyclist rides from the bottom of a slope to the top and gains 10000 J of gravitational potential energy. She rolls down her bicycle freely to the bottom of the slope, and her kinetic energy is 2000J.
How much energy is dissipated in overcoming friction.

The correct option is B 8000 J
Total energy is always conserved.
So, total energy at top = total energy at bottom
10000 J + 0 = 0 + 2000 J + energy lost due to friction
(10000 - 2000) J = energy lost due to friction
So, the energy lost due to friction = 8000 J