A cyclist starting from point $A$ travels $200 m$ due north to a point $B$ at a constant speed of $5 m / s$ . He rests at $B$ for $30 s e c$ and then travels $300 m$ due south to a point $C$ at a constant speed of $10 m / s$ . Find the average velocity. Take north as positive.

1 m / s

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- 1 m / s

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2 m / s

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- 2 m / s

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Solution

The correct option is B $- 1 m / s$
From $A$ to $B$
$x = 200 m; v = 5 m / s; t = 40 s e c$
From $B t o C$
Displacement $= 300 m$ ,
time taken $= 30 s e c$
Net Displacement $= - 100 m$
Total time $= 100 s e c$
Average velocity $= - \frac{100}{100} = - 1 m / s$

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A bird files due north at velocity 20 m/s for 15s it rests for 5s and then files due south at velocity 24 m/s for 10s. For the whole trip find the average speed and magnitude of average velocity.

Q. A truck travelling due to north at

30 m / s

turns west and travels at the same speed, then the change in velocity is :

Q. A river is flowing due east with a speed

3 \frac{m}{s}

. A swimmer can swim in still water at a speed of

4 \frac{m}{s}

(Figure).

(1) If swimmer starts swimming due north, what will be his resultant velocity (magnitude and direction)?

(2) If he wants to start from point

A

on south bank and reach opposite point

B

on north bank,
(a) which direction should he swim?
(b) what will be his resultant speed?

(3)

(i)

If swimmer starts swimming due north, what will be his resultant velocity (magnitude and direction)?

(i i)

If he wants to start from point

A

on south reach opposite point

B

on north bank, In which case will he reach opposite bank in time?

An airplane has to go from a point A to Point B, $500 k m$ away due $30 °$ East of the north. A wind is blowing due north at a speed of $20 m / s$ . The air speed of the plane is $150 m / s$ . Find the direction in which the pilot should head the plane to reach point B.

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A cyclist starting from point A travels 200 m due north to a point B at a constant speed of 5 m/s. He rests at B for 30 sec and then travels 300 m due south to a point C at a constant speed of 10 m/s. Find the average velocity. Take north as positive.

The correct option is B −1 m/sFrom A to B x=200 m; v=5 m/s; t=40 sec From B to C Displacement =300 m, time taken =30 sec Net Displacement =−100 m Total time =100 sec Average velocity =−100100=−1 m/s

A bird files due north at velocity 20 m/s for 15s it rests for 5s and then files due south at velocity 24 m/s for 10s. For the whole trip find the average speed and magnitude of average velocity.

A cyclist starting from point $A$ travels $200 m$ due north to a point $B$ at a constant speed of $5 m / s$ . He rests at $B$ for $30 s e c$ and then travels $300 m$ due south to a point $C$ at a constant speed of $10 m / s$ . Find the average velocity. Take north as positive.

The correct option is B $- 1 m / s$
From $A$ to $B$
$x = 200 m; v = 5 m / s; t = 40 s e c$
From $B t o C$
Displacement $= 300 m$ ,
time taken $= 30 s e c$
Net Displacement $= - 100 m$
Total time $= 100 s e c$
Average velocity $= - \frac{100}{100} = - 1 m / s$