A cyclist Travels a distance of 4 km from P to Q and then moves a distance of 3 km at right angles to PQ. Find the resultant displacement graphically
Given,
4 km from A to B
3 km at right angles to AB
The figure of the given situation
Displacement is the straight line distance between the initial and final position
So,
From the Pythagoras theorem
PR=√PQ2+QR2
Putting all the values
PR=√42+32
After solving
PR = 5 km
Hence the displacement is 5 km