Question

A cylinder can withstand a pressure of 15 atm. The pressure gauge of the cylinder indicates 12 atm at 27∘C. Above the cylinder will explode.

• A. ${88}^{\circ }C$
• B. ${110}^{\circ }C$
• C. ${102}^{\circ }C$
• D. ${115}^{\circ }C$

Answer 1

The correct option is C ${102}^{\circ }C$

Given, $P_1$ = 15 atm, $T_1$ = ?

$P_2$ = 12 atm, $T_2$ = 300 K (273+27)

Since the volume of the cylinder remains constant,
$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Therefore,$\frac{15}{T_1}=\frac{12}{300}$

$T_1$ = 375 K.

i.e., the cylinder will explode above 375 K or ${102}^{\circ }C$.