Question

A cylinder contained 10 kg of gas at pressure ${10}^{7}N/m^2.$ The quantity of gas taken out of cylinder if final pressure is $2.5\times {10}^{6}M/m$ is (assume the temperature of gas is constant)

• A. Zero
• B. 7.5 kg
• C. 2.5 kg
• D. 5 kg

Answer 1

The correct option is B 7.5 kg

At constant temperature for the given volume of gas $\frac{P_1}{P_2}=\frac{m_1}{m_2}$
$\therefore \frac{{10}^7}{2.5\times {10}^6}=\frac{10}{m_2}\Rightarrow m_2=\frac{2.5\times {10}^6\times 10}{{10}^7}=2.5kg$
$\therefore$ The quantity of gas taken out of the cylinder = 10 – 2.5 = 7.5 kg.