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Question

A cylinder containing 5 L of O2 at 25 C was leaking. When the leakage was detected and stopped, there was a change in the pressure of the gas from 3 atm to 2.235 atm. What volume of oxygen got leaked at 1 atm and 25 C?

A
4.8 L
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B
3.8 L
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C
2.8 L
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D
5.8 L
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Solution

The correct option is B 3.8 L
At P1=3.0 atm
n1=P1VRT=3VRT
At P2=2.235 atm
n2=2.235 atm
n2=P2VRT=2.235×VRT
No. of moles leaked n=n1n2
n=3VRT2.235 VRT
=0.765VRT
=0.765×50.0821×298
=0.156 mol
Volume of O2 leaked =nRTP=0.156×0.0821×2981=3.8 L

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