A cylinder containing 5 L of O2 at 25∘C was leaking. When the leakage was detected and stopped, there was a change in the pressure of the gas from 3 atm to 2.235 atm. What volume of oxygen got leaked at 1 atm and 25∘C?
A
4.8 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.8 L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.8 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.8 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 3.8 L At P1=3.0 atm n1=P1VRT=3VRT At P2=2.235 atm n2=2.235 atm n2=P2VRT=2.235×VRT ∴ No. of moles leaked n=n1−n2 n=3VRT−2.235VRT =0.765VRT =0.765×50.0821×298 =0.156 mol ∴ Volume of O2 leaked =nRTP=0.156×0.0821×2981=3.8L