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Standard X

Physics

Ideal Gas Equation

A cylinder co...

Question

A cylinder contains $10$ kg of gas at a pressure of $10^{7}$ N $m^{- 2}$ . The quantity of gas taken out of the cylinder, if final pressure is $2.5 \times 10^{6}$ N $m^{- 2}$ is?

9.5

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7.5

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14.2

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Solution

The correct option is B $7.5$ kg
$\frac{P_{1}}{P_{2}} = \frac{ρ_{1}}{ρ_{2}} = \frac{m_{1}}{m_{2}}$
$m_{2} = \frac{P_{2}}{P_{1}} \times m_{1} = \frac{2.5 \times 10^{6}}{10^{7}} \times 10 = 2.5$ kg
Mass of gas taken out $= 10 - 2.5 = 7.5$ kg.

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A cylinder contains 10kg of gas at a pressure of 107N m−2. The quantity of gas taken out of the cylinder, if final pressure is 2.5×106N m−2 is?

The correct option is B 7.5kgP1P2=ρ1ρ2=m1m2m2=P2P1×m1=2.5×106107×10=2.5kgMass of gas taken out =10−2.5=7.5kg.

A cylinder contains $10$ kg of gas at a pressure of $10^{7}$ N $m^{- 2}$ . The quantity of gas taken out of the cylinder, if final pressure is $2.5 \times 10^{6}$ N $m^{- 2}$ is?

The correct option is B $7.5$ kg
$\frac{P_{1}}{P_{2}} = \frac{ρ_{1}}{ρ_{2}} = \frac{m_{1}}{m_{2}}$
$m_{2} = \frac{P_{2}}{P_{1}} \times m_{1} = \frac{2.5 \times 10^{6}}{10^{7}} \times 10 = 2.5$ kg
Mass of gas taken out $= 10 - 2.5 = 7.5$ kg.