Question

A cylinder contains $68g$ of ammonia gas at s.t.p.
What is the volume occupied by this gas?

Answer 1

The molecular weight of $N{H}_3$ = 14+3 = 17.

If 17 g of $N{H}_3$ contains 22.4$l$ at STP

Then 68g of $N{H}_3$ contains = $\frac{22.4}{17}\times 68=89.6l$