Question

A cylinder contains a gas at temperature of ${27}^{o}C$ and a pressure $IMPa$. If the temperature of the gas Is lowered to $-{23}^{o}C$, the change in pressure is:

• A. $1MPa$
• B. $5/6MPa$
• C. $1/6MPa$
• D. $5MPa$

Answer 1

The correct option is C $1/6MPa$

$T_1={27}^{\circ }C=300k,T_L=-23C=250K$

$P_1=1mPa{P}_2=?$

Acc. to charls law

$\frac{P_1}{T_1}=\frac{P_L}{T_L}\Rightarrow \frac{1}{300}=\frac{P_2}{250}$

$P_2=\frac{5}{6}MPa$

\mathrm{P}=\frac{1}{6} \mathrm{mPa}$

Answer: $\left(C\right)\frac{1}{6}MPa$