A cylinder has some water at height 20 cm. If a sphere of radius 6 cm is poured into it then find the rise in height of water if the radius of cylinder is 4 cm

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Solution

Volume of sphere=Volume of rise of water in cylinder
$\frac{4}{3} π r^{3}$ $= π R^{2} H$
$\frac{4}{3} \times 6^{3}$ $= 4^{2} \times H$
On solving we get $H = 18 c m$

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A cylinder has some water at height 20 cm. If a sphere of radius 6 cm is poured into it then find the rise in height of water if the radius of cylinder is 4 cm

Volume of sphere=Volume of rise of water in cylinder43πr3=πR2H43×63=42×HOn solving we get H=18cm

Volume of sphere=Volume of rise of water in cylinder
$\frac{4}{3} π r^{3}$ $= π R^{2} H$
$\frac{4}{3} \times 6^{3}$ $= 4^{2} \times H$
On solving we get $H = 18 c m$