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Question

A cylinder is rolling without sliding over two horizontal planks (surfaces) 1 and 2. If the velocities of the surfaces A and B are v^i and 2v^i respectively. Then,
157342_5baa2b88a0104e34aa2d08c49d795c54.png

A
position of instantaneous axis of rotation is 2R3
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B
position of instantaneous axis of rotation is 4R3
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C
angular velocity of the cylinder is 5v/2R
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D
angular velocity of the cylinder is 3v/2R
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Solution

The correct options are
A position of instantaneous axis of rotation is 2R3
D angular velocity of the cylinder is 3v/2R

Let v1 be the velocity of COM of cylinder and w be its angular velocity.
Let C be the position of instantaneous axis of rotation.
2v=w(CB)2v=(2Rx)w ...........(a)
v=xw ............(b)
2(wx)=(2Rx)wx=2R3
Also there is no slipping at A and B.
Thus 2v=v1+Rw and v=Rwv1
Eliminating v1, we get w=3v2R

446045_157342_ans_d80b13b4497145f187ef749199cea3ed.png

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