wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cylinder is sandwiched between two planks. Two constant horizontal forces F and 2F are applied on the planks as shown. If there is no slipping at the top and bottom of cylinder, then
219429_0ba0d92b51c94ffdb91e4ed231fcc97a.png

A
acceleration of the centre of mass of cylinder is 21F26M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
acceleration of the centre of mass of cylinder is 13F26M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
acceleration of the top plank is F26M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
acceleration of the top plank is F13M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A acceleration of the centre of mass of cylinder is 21F26M
C acceleration of the top plank is F26M
Equations of motion are,
F+f1=Ma1...(i)
f1+f2=Ma2...(ii)
2Ff2=2Ma3...(iii)
α=(f1f2)R12MR2
or α=2(f1f2)MR....(iv)
For no slipping condition. a2+Rα=a1...(v) and
a2Rα=a3...(vi)
We have six unknowns,f1,f2,a1,a2,a3 and α Solving the above six equations. we get
a1=21F26M and a2=F26M
802723_219429_ans_c57f6301a5814a23bfe0d372c7759a9b.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Springs: Playing with a Slinky
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon