A cylinder of $5 L$ capacity, filled with air at $N T P$ is connected with another evacuated cylinder of $30 L$ capacity. The resultant air pressure in both the cylinder will be:

10.8 c m

H g

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14.9 c m

H g

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21.8 c m

H g

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38.8 c m

H g

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Solution

The correct option is A $10.8 c m$ of $H g$
Boyle's law states that $P_{1} V_{1} = P_{2} V_{2}$
Here, at $N T P$ , pressure $= 76$ cm of $H g = P_{1}$
$V_{1} = 5 L$
$V_{2} = 30 L + 5 L$

Now
$P_{1} \times (5) = P_{2} \times (35)$

$P_{1} = 7 P_{2}$

$P_{2} = 76 / 7 = 10.8 c m o f H g$

So, pressure in both cylender $= 10.8$ cm

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