A cylinder of 5 litres capacity, filled with air at NTP is connected with another evacuated cylinder of 30 litres of capacity. The resultant air pressure in both the cylinders will

10.8 cm of Hg

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21.8 cm of Hg

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38.8 cm of Hg

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Solution

The correct option is A 10.8 cm of Hg
$P_{1}$ = 76 cm Hg (Initial pressure at N.T.P.)
$P_{2}$ = ? , $V_{1}$ = 5 litre , $V_{2}$ = 30 + 5 = 35 litres

According to Boyle's law
$P_{1}$ $V_{1}$ = $P_{2}$ $V_{2}$ ; 76 $\times$ 5 = $P_{2}$ $\times$ 35
$P_{2}$ = $\frac{76 \times 5}{35} \Rightarrow P_{2}$ = 10.8 cm of Hg

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A cylinder of 5 litres capacity, filled with air at NTP is connected with another evacuated cylinder of 30 litres of capacity. The resultant air pressure in both the cylinders will

The correct option is A 10.8 cm of HgP1 = 76 cm Hg (Initial pressure at N.T.P.) P2 = ? , V1 = 5 litre , V2 = 30 + 5 = 35 litres According to Boyle's law P1 V1 = P2 V2; 76 × 5 = P2 × 35 P2 = 76×535⇒P2 = 10.8 cm of Hg