A cylinder of fixed capacity (of 44.8L) contains 2 moles of He gas at STP. What is the amount of heat needed to raise the temperature of the gas in the cylinder by 20∘C? [R = 8.31 J/molK]
A
996J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
831J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
499J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
374J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 499J Cylinder is of fixed capacity (volume constant) Q=nCvΔT if volume constant Q=nCVΔT if pressure Q=nCPΔT constant n=2mol,Cv(Hegas)=32R,ΔT=20K Q=2×32×8.31×20 =498.6J=499J