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Question

A cylinder of gas supplied by a company contains 14 kg of butane. The heat of combustion of butane is 2658kJmol1. A normal family requires 20 MJ of energy per day for cooking. If the cylinder lasts for 26 days, the percentage of gas that is wasted due to insufficient combustion is _______.

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Solution

The molar mass of butane is 58.12 g/mol.
14 kg of butane corresponds to 14000g58.12g/mol=240.88mol
The maximum energy that can be obtained if there is no wastage is =2658kJ/mol×240.88mol=640259kJ=640.259MJ
The energy consumed by the family =20MJ/day×26day=520MJ
The percentage of gas wasted due to insufficient combustion is =640.259520640.259×100=18.78 %

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