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Enthalpy of Combustion

A cylinder of...

Question

A cylinder of gas supplied by a company contains 14 kg of butane. The heat of combustion of butane is $2658 k J m o l^{- 1}$ . A normal family requires $20 M J$ of energy per day for cooking. If the cylinder lasts for 26 days, the percentage of gas that is wasted due to insufficient combustion is _______.

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Solution

The molar mass of butane is 58.12 g/mol.
14 kg of butane corresponds to $\frac{14000 g}{58.12 g / m o l} = 240.88 m o l$
The maximum energy that can be obtained if there is no wastage is $= 2658 k J / m o l \times 240.88 m o l = 640259 k J = 640.259 M J$
The energy consumed by the family $= 20 M J / d a y \times 26 d a y = 520 M J$
The percentage of gas wasted due to insufficient combustion is $= \frac{640.259 - 520}{640.259} \times 100 = 18.78$ %

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