A cylinder of mass 5 kg and radius 4 m is rolling purely on a horizontal surface. What will be the angular momentum of the cylinder with respect to any point on the ground if its centre of mass moves with the velocity of 20 m/s?
A
800Kg−m2s
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B
600Kg−m2s
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C
1000Kg−m2s
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D
400Kg−m2s
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Solution
The correct option is B600Kg−m2s As explained in the previous videoclip, L=Iω+mRVcm =mR22ω+mRVcm
also, V = Rω ⇒L=5(4)252+5.20×4 =200+400=600kg−m2s