Question

a cylinder of radius R and length L is placed in a uniform electric field E parallel to cylinder axis.what is the outward flux over the surface of cylinder ??

Answer 1

$$\begin{gathered} \mathrm{The}\mathrm{electric}\mathrm{flux}\mathrm{entering}\mathrm{and}\mathrm{leaving}\mathrm{the}\mathrm{cylindrical}\mathrm{surface}\mathrm{is}\mathrm{same}. \\ \mathrm{\varphi }={\mathrm{E\pi R}}^2-{\mathrm{E\pi R}}^2=0 \\ \mathrm{where},\mathrm{E}=\mathrm{electric}\mathrm{field} \\ \mathrm{R}=\mathrm{radius}\mathrm{of}\mathrm{cylinder} \\ \mathrm{\varphi }=\mathrm{outward}\mathrm{flux} \end{gathered}$$