Question

A cylinder rolls on a horizontal place surface. If the speed of the centre is 25 m/s, what is the speed of the highest point?

Answer 1

Let v_c be the translational velocity of the cylinder.
Let ω be the rotational velocity of the cylinder.
Let r be the radius of the cylinder.
For rolling, we have:
v_c = rω



Speed of the highest point = v_c + rω = 2v_c
⇒ $2\times 25\mathrm{m}/\mathrm{s}$ = 50 m/s