The correct option is D The motion of the block is symmetric about its equilibrium position.
Since liquid 2 is below liquid 1, liquid 2 is denser than liquid 1.
Let the area of cross-section of the cylindrical block be A and it is displaced downwards by y. Then, the volume of liquid 2 displaced will increase by Ay and that of liquid 1 will decrease by the same amount Ay.
Hence, net increase in upthrust on the block will be equal to (Ayd2g−Ayd1g). This additional upthrust will try to restore the block to the original position.
Net restoring force =Ay(d2−d1)g.
Since this force is restoring and directly proportional to displacement y, the cylindrical block will execute SHM along a vertical line.
Hence, option (a) is correct and option (b) is wrong.
If the mass of the block is equal to m, then its acceleration will be equal to Ayg(d2−d1)m.
Since, its acceleration depends on mass m, frequency of oscillations will depend on the size of the cylindrical block.
Hence, option (c) is wrong.
If the cylinder is displaced upward through y from equilibrium position, then it will experience a net downward force equal to the calculated value above. This shows that its motion will be symmetric about its equilibrium position.
Hence, option (a) and (d) are correct.