A cylindrical can whose base is horizontal and of radius 3.5 cm contains sufficient water so that when a sphere is placed in the can, the water just covers the sphere. Given that the sphere just fits into the can,

Calculate:
(i) the total surface area of the can in contact with water when the sphere is in it.
(ii) the depth of water in the can before the sphere was put into the can.

Take π as ²²/₇ and give your answers as proper fractions.

Q.

A cylindrical can, whose base is horizontal and of radius 3.5 cm, contains sufficient water so that when a sphere is placed in the can, the water just covers the sphere. Given that the sphere just fits into the can, calculate :
(i) the total surface area of the can in contact with water when the sphere is in it;
(ii) the depth of water in the can before the sphere was put into the can.

Q. A cylindrical can whose base is horizontal and is of internal radius $3.5$ cm contains sufficient water so that when a solid sphere is placed inside, water just covers the sphere. The sphere fits in the can exactly. The depth of water in the can before the sphere was put, is

Q.

A cylindrical can of internal diameter 21 cm contains water . A solid sphere whose diameter is 10.5 cm is lowered into the cylindrical can. The sphere is completely immersed in water . Calculate the rise in water level, assuming that no water overflows.

Q. If a solid sphere of $3cm$ radius is melted and re-casted into a right circular cone whose base radius is same as that of the sphere, the height of the cone will be:

Q. A tank measuring $22\ast 9\ast 10$. Its half full of water. A solid metal sphere with radius 3cm is placed into the tank. Assuming that the sphere sinks to the bottom of the tank calculate the rise in height of water in cms