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Question

A cylindrical cavity of diameter a exists inside a cylinder of diameter 2a as shown in the figure. Both the cylinder and the cavity are nfinitely long. A uniform current density j flows along the length. If the magnitude of the magnetic filed at the point P is given by N12μ0aj, then the value of N is

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Solution

For rR,B=μ0I2πR2.r=μ0jπR22πR2.r=μ0jr2

For r>R,B=μ0I2πr=μ0jπR22πr=μ0jR22r


Magnetic field due to the cylinder at P is
B1=μ0ja2

Magnetic field due to the cavity at P is

B2μ0j(a2)22(3a2)2=μ0ja12

Net magnetic field at point P is

B=B1B2=μ0ja2(116)=5μ0ja12=Nμ0ja12

Hence, N=5


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