A cylindrical conductor of length L and uniform area of cross-section A has resistance R. Another conductor of length 2L and resistance R of the same material has an area of cross-section:
A
A/2
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B
3A/2
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C
2A
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D
3A
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Solution
The correct option is C 2A Hint: Recall the relation between resistance and resistivity of a conductor.
Step 1: Evaluation of resistance of the first conductor in terms of resistivity.
We know that, R=ρLA
ρ is the resistivity of the cylindrical conductor.
Step 2: Evaluation of resistance of the second conductor in terms of resistivity.
We know that, R′=ρ2LA′
A′ is the unknown cross section of the second conductor. Step 3: Comparing the two expressions
Since R′=R (Given)
or, ρLA=ρ2LA′
A′=2A
Final Step : The second conductor of length 2L and resistance R has an area of 2A