A cylindrical conductor of length(l) and uniform area of cross section. A has resistance R another conductor of length 2.5 l and resistance 0.5R of same material has area of cross section. a) 5A b)2.5A. c)0.5A. d)1/5A

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Solution

Dear Student

R= ρ $\frac{l}{A}$

$\frac{R_{1}}{R_{2}} = \frac{l_{1}}{l_{2}} \frac{A_{2}}{A_{1}}$
Thus
A₂= $\frac{R_{1} l_{2} A_{1}}{R_{2} l_{1}}$ = 5A

Thus answer is a)5A

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