wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cylindrical conductor of radius R carries a current I. The value of the magnetic field at a point which is at R/4 distance inside from the surface is 10 T. Find the value of the magnetic field at a point which is at a 4R distance outside from the surface


A
43T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
83T
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
403T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
803T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 83T
Bin=μo4π2irR2
Now, magnetic field outside the cylinder at a distance r' from its axis,
Bout=μo4π2ir
Now, we have
BinBout=rrR2
10Bout=(RR/4)(R+4R)R2
Bout=83T

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ampere's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon