A cylindrical container of diameter 42 m and height 24 m is full of diesel. The diesel is emptied into a rectangular pool of length 132 m and breadth 56 m. Find the height of which diesel rises in pool.

22 m

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18 m

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9 m

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4.5 m

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Solution

The correct option is D
4.5 m

Volume of cylindrical container = $π r^{2} h$

$= \frac{22}{7} \times (21 m)^{2} \times 24$ $= 33264 m^{3}$

Rise in the height of diesel in pool $\times$ length of pool $\times$ breadth of pool = Volume of cylindrical container

Rise in the height of diesel in pool = $\frac{V o l u m e o f c y l i n d r i c a l c o n t a i n e r}{(l e n g t h o f p o o l) (b r e a d t h o f p o o l)}$

$= \frac{33264 m^{3}}{132 m \times 56 m}$

$= 4.5 m$

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