A cylindrical container with diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 22 cm $\times$ 14 cm $\times$ 10.5 cm. Find the rise in level of the water when the solid is submerged.

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Solution

When the solid is submerged in water it displaces its own volume.

The volume of the rectangular block is :

Volume = Length × Width × height
Volume = 22 × 14 × 10.5 = 3234 $c m^{3}$

The volume of a cylinder = $π r^{2} h$

The rise in height is :

3234 = × h

3234 = × 21 × h

3234 = 66h

h =

h = 49 cm

The water rises by 49 cm

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Q. A cylinder container with diameter of base

42

cm contains sufficient water to submerge a rectangular solid of iron with dimensions

22

\times 14

\times 10.5

cm. Find the rise in the level of the water when the solid is submerged.

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A cylindrical container with diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 22 cm × 14 cm × 10.5 cm. Find the rise in level of the water when the solid is submerged.

A cylindrical container with diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 22 cm $\times$ 14 cm $\times$ 10.5 cm. Find the rise in level of the water when the solid is submerged.