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Question

A cylindrical metal tube has a length of 50 cm and is , open at both ends. Find the frequencies between 1000 Hz and 2000 Hz at which the air column in the tube can resonate. Speed of sound in air is 340ms1.

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Solution

Here given that,

I =50 cm, v=340 m/s

As it is an open organ pipe the fundamental frequency,

f1=(v2I)

=3402×50×102=340 Hertz

So the harmonics are,

f3=3×340=1020Hz

f5=5×340=1700Hz

f6=6×340=2040Hz

So the possible frequecies are between 1000 Hz and 2000 Hz are 1020,1360,1700.


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