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Magnetic Field

A cylindrical...

Question

A cylindrical rod magnet has a length of 5 cm and a diameter of 1 cm. it has a uniform magnetisation of $5.30 \times 10^{3} A m p / m^{3}$ .what is its magnetic dipole moment?

A

1 \times 10^{- 2} J / T

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B

2.08 \times 10^{- 2} J / T

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C

3.08 \times 10^{- 2} J / T

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D

1.52 \times 10^{- 2} J / T

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Solution

The correct option is A $2.08 \times 10^{- 2} J / T$

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