A cylindrical roller $2.5 m$ in length, $1.75 m$ in radius when rolled on a road was found to cover the area of $5500 m^{2}$ . How many revolutions did it make?

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Solution

Area covered by cylindrical roller in one revolution $=$ Curved surface area of cylinder

Curved surface of cylinder $= 2 π r \times l = 2 π \times (1.75) (2.5) = 27.5 m^{2}$
Revolution $= \frac{Total Area}{Area covered in one revolution} = \frac{5500}{27.5} = 200$

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A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. How many revolutions did it make?

Area covered by cylindrical roller in one revolution = Curved surface area of cylinderCurved surface of cylinder =2πr×l=2π×(1.75)(2.5)=27.5 m2Revolution =Total AreaArea covered in one revolution=550027.5=200

A cylindrical roller $2.5 m$ in length, $1.75 m$ in radius when rolled on a road was found to cover the area of $5500 m^{2}$ . How many revolutions did it make?

Area covered by cylindrical roller in one revolution $=$ Curved surface area of cylinder

Curved surface of cylinder $= 2 π r \times l = 2 π \times (1.75) (2.5) = 27.5 m^{2}$
Revolution $= \frac{Total Area}{Area covered in one revolution} = \frac{5500}{27.5} = 200$