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Question

A cylindrical source of light which emits radiation radially (from a curved surface) only, placed at the center of a hollow, metallic cylindrical surface, as shown in the diagram.
The power of the source is 90 watt and it emits light of wavelength 4000 A only. The emitted photons strike the metallic cylindrical surface which results in the ejection of photoelectrons. All ejected photoelectrons reach the anode (light source). The magnitude of photocurrent in amp is [Given:h=6.4×1034J/sec].
131929_9bb16d775dd94ba4bc4ff4b395d2e86f.png

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Solution

Power is 90 W. It corresponds to 90 J/s.
The energy of one photon is E=hcλ=6.4×1034×3×1084000×1010=4.8×1019

Number of photon emitted per second =904.8×1019=1.875×1020

Number of photoelectrons emitted per second =120360×1.875×1020=6.25×1019

Electric current =6.25×1019×1.602×1019=10A

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