1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A cylindrical source of light which emits radiation radially (from a curved surface) only, placed at the center of a hollow, metallic cylindrical surface, as shown in the diagram.The power of the source is 90 watt and it emits light of wavelength 4000 A only. The emitted photons strike the metallic cylindrical surface which results in the ejection of photoelectrons. All ejected photoelectrons reach the anode (light source). The magnitude of photocurrent in amp is [Given:h=6.4×10−34J/sec].

Open in App
Solution

## Power is 90 W. It corresponds to 90 J/s.The energy of one photon is E=hcλ=6.4×10−34×3×1084000×10−10=4.8×10−19Number of photon emitted per second =904.8×10−19=1.875×1020Number of photoelectrons emitted per second =120360×1.875×1020=6.25×1019Electric current =6.25×1019×1.602×10−19=10A

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Magnetic Force
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program