A cylindrical tank has a hole of 2cm^2 at its bottom . if water is allowed to flow into tank from a tube above it at a rate of 100cm^3/s, then find maximum height upto which water can rise up in tank ?

Open in App

Solution

The height of water in the tank becomes maximum when the volume of water flowing into the tank per second becomes equal to the volume flowing out per second.

=Av = A√2gh ...(i)

Volume of water flowing in per second

=100cm3/sec ...(ii)

A=2 cm^2/sec

From (i) and (ii) we get

A√2gh=100
=
⇒2×√2×980×h=100

=> h=2500/(980×2)

=> h=1.275cm.

•note
# All units are in cm.so we also used the value of g in cm/s.
(g=9.8m/s =980cm/s )

Suggest Corrections

Similar questions

A cylindrical tank has a hole of 1 $c m^{2}$ in its bottom. If the water is allowed to flow into the tank from a tube above it at the rate of 70 $c m^{3}$ /sec. then the maximum height up to which water can rise in the tank is

Q. A cylindrical tank has a hole of

1

c m^{2}

m bottom. If the water is allowed to flow into the tank from a tube above it at the rate of

70 c m^{2} / s

, then the maximum height up to which water can rise in the tank is?

Q. A cylindrical tank has a hole of

1 c m^{2}

in its bottom. If the water is allowed to flow into the tank from a tube above it at the rate of

70 c m^{3} / s e c

. then the maximum height up to which water can rise in the tank is

Q. A cylindrical tank has a hole of area

1 {cm}^{2}

at its bottom. If water is allowed to flow into the tank from a tube above it at the rate of

70 {cm}^{3} / sec

, then the maximum height up to which water can rise in the tank is -
[Take

g = 980 {cm/s}^{2}

]

Q. A cylindrical tank has a hole of area

1 {cm}^{2}

at its bottom. If water is allowed to flow into the tank from a tube above it at the rate of

70 {cm}^{3} / sec

, then the maximum height up to which water can rise in the tank is -
[Take

g = 980 {cm/s}^{2}

]

Join BYJU'S Learning Program