A cylindrical tank of radius 10 m is being filled with water at the rate of 314 cubic meter per hour. Then the depth of the water is increasing at the rate of
Given, radius of cylindrical tank r=10 m
And,
dVdt=314m3h
We know that volume of cylindrical tank is,
V=πr2h
⇒V=π(10)2h
⇒V=100πh
Differentiating w.r.t t
dVdt=100π(dhdt)
⇒314=100π(dhdt)
⇒(dhdt)=314100×3.14=1
∴dhdt=1 m/h
So, option (A) is the correct answer .