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Question

A cylindrical tub radius 12 cm contains water to a depth of 20 cm. A spherical ball is dropped into the tub and the level of the water is raised by 6.75 cn. Find the radius of the ball.


Solution

We have

Radius of cylinder(r)=12 m

Initial height of the cylinder (h) = 20 cm

Final height of the cylinder (H)= (20 + 6.75) cm

 =26.75 cm

So,

Volume of the sphere = Volume of cylinder at final height - Volume of cylinder at initial height 

43πR3=πr2Hπr2h

43R3=r2(Hh)

36.75×14434

3729=9

Hence radius is 9 cm


Mathematics
RD Sharma
Standard X

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