A cylindrical tube open at both ends has a fundamental frequency f in air. The tube is dipped vertically in water so that it has water up to the half height. The fundamental frequency of the air column is now (Neglect end corrections)
A
4f
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B
3f
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C
f
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D
2f
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Solution
The correct option is Cf For open organ pipe, fundamental frequency, f=v2l, where l is the length of an organ pipe. ⇒l=v2f After the pipe is half dipped in water, it becomes a closed organ pipe and its new length is, l′=v4f So, fundamental frequency of closed organ pipe, f′=v4l′ [speed is same as medium is same] ⇒f′=v4×v4f=f