Question

A cylindrical tube, open at both ends, has a fundamental frequency, v, in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column now is

• A. $\frac{v}{2}$
• B. $v$
• C. $\frac{3v}{4}$
• D. $2v$

Answer 1

Answer: (A), (B)

$\frac{v}{2}$
$v$

$f=\frac{v}{2l}$

Now, it will act as one end open and one end closed.

So, $f_0=\frac{v}{2l^{\prime }}=\frac{v}{4\frac{l}{2}}=\frac{v}{2l}=f$