A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. the metal everywhere is 0.4 cm thick. The volume of the metal is -

280.52 cm³

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306.24 cm³

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310 cm³

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316 cm³

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327 cm³

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Solution

The correct option is B
306.24 cm³

Internal radius = $(\frac{11.2}{2})$ cm = 5.6 cm, external radius = (5.6+0.4) cm = 6 cm.

Volume of metal = $\frac{22}{7} \times [(6)^{2} - (5.6)^{2}] \times 21$ cm $^{3}$ = (66 $\times$ 11.6 $\times$ 0.4) cm $^{3}$ = 306.24 cm $^{3}$ .

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A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. the metal everywhere is 0.4 cm thick. The volume of the metal is -

The correct option is B 306.24 cm3 Internal radius = (11.22)cm = 5.6 cm, external radius = (5.6+0.4) cm = 6 cm. Volume of metal = 227×[(6)2−(5.6)2]×21 cm3= (66 × 11.6 × 0.4) cm3= 306.24 cm3.

The correct option is B
306.24 cm³

Internal radius = $(\frac{11.2}{2})$ cm = 5.6 cm, external radius = (5.6+0.4) cm = 6 cm.

Volume of metal = $\frac{22}{7} \times [(6)^{2} - (5.6)^{2}] \times 21$ cm $^{3}$ = (66 $\times$ 11.6 $\times$ 0.4) cm $^{3}$ = 306.24 cm $^{3}$ .