Question

A cylindrical tube, open at both ends, is made of metal. The internal diameter of tube, is 10 cm. and its length is 25 cm. The thickness of the metal is 8 mm everywhere. Calculate the volume of the metal.

Answer 1

If cylinder has inner diameter is 10.4cm and thickness is 8mm=0.8cm
therefore outer diameter is 11.2cm
therefore volume with outer diameter is
=$\pi r^{2}h=3.14\times 11.2\times 11.2\times 25=9847.04c{m}^3$
and volume with diameter inner 10.4cm is
=$3.14\times 10.4\times 10.4\times 25=8490.56c{m}^3$
Now volume of metal is
=9847.04-8490.56=1356.48$c{m}^3$