Question

A cylindrical vessel filled with water is released on an inclined surface of angle $\theta$ as shown in figure. The friction coefficient of surface with vessel is $\mu (<\tan \theta )$. Then the constant angle made by the surface of water with the incline will be.

• A. ${\tan }^{-1}\mu$
• B. $\theta -{\tan }^{-1}\mu$
• C. $\theta +{\tan }^{-1}\mu$
• D. ${\cot }^{-1}\mu$

Answer 1

The correct option is A ${\tan }^{-1}\mu$

Since frictional force = pulling force

i.e. $\mu mgcos\theta =mgsin\theta$

$tan\theta =\mu$

$\theta ={tan}^{-1}\mu$

here $\theta$ is angle made by surface of water with incline