A cylindrical vessel of base radius $14$ cm is filled with water to some height . if a rectangular solid of dimensions $22$ cm $\times 7$ cm $\times$ $5$ cm is immersed in it, what is the rise in the water level ?

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1.25

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Solution

The correct option is B $1.25$ cm
Radius of cylinder $= 14 c m$
Volume of rectangular solid $= 22 \times 7 \times 5 = 770 c m^{3}$
Rise in height of water $= \frac{770}{π R^{2}} = \frac{770}{\frac{22}{7} \times 14 \times 14} = \frac{770 \times 7}{22 \times 14 \times 14} = 1.25 c m$

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A cylindrical vessel of base radius 14 cm is filled with water to some height . if a rectangular solid of dimensions 22 cm ×7 cm × 5 cm is immersed in it, what is the rise in the water level ?

The correct option is B 1.25 cmRadius of cylinder=14cmVolume of rectangular solid=22×7×5=770cm3Rise in height of water =770πR2=770227×14×14=770×722×14×14=1.25cm

A cylindrical vessel of base radius $14$ cm is filled with water to some height . if a rectangular solid of dimensions $22$ cm $\times 7$ cm $\times$ $5$ cm is immersed in it, what is the rise in the water level ?

The correct option is B $1.25$ cm
Radius of cylinder $= 14 c m$
Volume of rectangular solid $= 22 \times 7 \times 5 = 770 c m^{3}$
Rise in height of water $= \frac{770}{π R^{2}} = \frac{770}{\frac{22}{7} \times 14 \times 14} = \frac{770 \times 7}{22 \times 14 \times 14} = 1.25 c m$