Question

A cylindrical vessel, without lid, has to be tin-coated including both of its sides. If the radius of its base is $\frac{1}{2}m$ and its height is $1.4m$, calculate the cost of tin-coating at the rate of Rs.$50$ per $1000{cm}^2$ (Use $\pi =3.14$)

• A. Rs.$5181$
• B. Rs.$5180$
• C. Rs.$5081$
• D. Rs.$4181$

Answer 1

The correct option is A Rs.$5181$

Radius of the base $\left(r\right)=\frac{1}{2}m=\frac{1}{2}\times 100cm=50cm$
Height $\left(h\right)=1.4m=1.4\times 100cm=140cm$
Surface area to be tin-coated$=2(2\pi rh+\pi r^2)$
$=2(2\times 3.14\times 50\times 140+3.14\times {(50}^2$
$=2(43960+7850)=2\left(51810\right)=103620{cm}^2$
$\therefore$ Cost of tin-coating at the rate of Rs.$50$ per $1000{cm}^2=$Rs.$\frac{50}{1000}\times 103620=$ Rs.$5181$